Abstract
The problem of triangulating a polygon using the minimum number of triangles is treated. We show that the minimum number of triangles required to partition a simple n-gon is equal to n+2 w -d - 2, where w is the number of holes and d is the maximum number of independent degenerate triangles of the n-gon. We also propose an algorithm for constructing the minimum triangulation of a simple hole-free n-gon. The algorithm takes O(nlog2n+DK2) time, where D is the maximum number of vertices lying on the same line in the n-gon and K is the number of minimally degenerate triangles of the n-gon.
Original language | English |
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Pages (from-to) | 570-582 |
Number of pages | 13 |
Journal | BIT |
Volume | 30 |
Issue number | 4 |
DOIs | |
State | Published - 1 Dec 1990 |
Keywords
- G.1.6
- I.1.2
- I.3.5